输入一棵二叉树,求该树的深度。从根结点到叶结点依次经过的结点(含根、叶结点)形成树的一条路径,最长路径的长度为树的深度
递归写法,比较简单
public class Solution { public int TreeDepth(TreeNode root) { if(root == null) { return 0; } int left = TreeDepth(root.left); int right = TreeDepth(root.right); return Math.max(left, right) + 1; } }非递归写法
depth 是当前结点所在的层数,count 是已经遍历过的结点数,nextCount 是下层的结点总数,当 count == nextCount 的时候,代表本层的节点已经遍历完毕
import java.util.LinkedList; import java.util.Queue; public class Solution { public int TreeDepth(TreeNode root) { if(root == null) { return 0; } Queue<TreeNode> queue = new LinkedList<>(); queue.add(root); int depth = 0, count = 0, nextCount = 1; while(queue.size() != 0) { TreeNode top = queue.poll(); count++; if(top.left != null) { queue.add(top.left); } if(top.right != null) { queue.add(top.right); } if(count == nextCount) { nextCount = queue.size(); count = 0; depth++; } } return depth; } }