xctf crackme

it2026-09-21  2

xctf crackme 文件用ida打开 发现有壳,查壳发现nspack壳 我用工具没有成功,没办法只能手脱

脱壳参考这位大佬 脱壳成功 逻辑简单 最后贴上我的payload

a= [ 0x00000012, 0x00000004, 0x00000008, 0x00000014, 0x00000024, 0x0000005C, 0x0000004A, 0x0000003D, 0x00000056, 0x0000000A, 0x00000010, 0x00000067, 0x00000000, 0x00000041, 0x00000000, 0x00000001, 0x00000046, 0x0000005A, 0x00000044, 0x00000042, 0x0000006E, 0x0000000C, 0x00000044, 0x00000072, 0x0000000C, 0x0000000D, 0x00000040, 0x0000003E, 0x0000004B, 0x0000005F, 0x00000002, 0x00000001, 0x0000004C, 0x0000005E, 0x0000005B, 0x00000017, 0x0000006E, 0x0000000C, 0x00000016, 0x00000068, 0x0000005B, 0x00000012,0x48,0x0e] s="this_is_not_flag" flag='' for i in range(42): flag+=chr(ord(s[i%16])^a[i]) print(flag)

总结:这道题逻辑还是比较简单的,主要还是脱壳要成功

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