题意：

给你n个木棍的长度和重量，让其成为上升序列，如果不能达到，就需要重新一分钟设置。 a）第一个木棍的准备时间为1分钟。 b）在处理长度为l和重量为w的棒之后，如果l <= l’并且w <= w’，则机器将不需要设置长度为l’和重量为w’的棒的设置时间。否则，将需要1分钟进行设置。

题目：

There is a pile of n wooden sticks. The length and weight of each stick are known in advance. The sticks are to be processed by a woodworking machine in one by one fashion. It needs some time, called setup time, for the machine to prepare processing a stick. The setup times are associated with cleaning operations and changing tools and shapes in the machine. The setup times of the woodworking machine are given as follows: (a) The setup time for the first wooden stick is 1 minute. (b) Right after processing a stick of length l and weight w , the machine will need no setup time for a stick of length l’ and weight w’ if l <= l’ and w <= w’. Otherwise, it will need 1 minute for setup. You are to find the minimum setup time to process a given pile of n wooden sticks. For example, if you have five sticks whose pairs of length and weight are ( 9 , 4 ) , ( 2 , 5 ) , ( 1 , 2 ) , ( 5 , 3 ) , and ( 4 , 1 ) , then the minimum setup time should be 2 minutes since there is a sequence of pairs ( 4 , 1 ) , ( 5 , 3 ) , ( 9 , 4 ) , ( 1 , 2 ) , ( 2 , 5 ) .

Input

The input consists of T test cases. The number of test cases (T) is given in the first line of the input file. Each test case consists of two lines: The first line has an integer n , 1 <= n <= 5000 , that represents the number of wooden sticks in the test case, and the second line contains 2n positive integers l1 , w1 , l2 , w2 ,…, ln , wn , each of magnitude at most 10000 , where li and wi are the length and weight of the i th wooden stick, respectively. The 2n integers are delimited by one or more spaces.

Output

The output should contain the minimum setup time in minutes, one per line.

Sample Input

3 5 4 9 5 2 2 1 3 5 1 4 3 2 2 1 1 2 2 3 1 3 2 2 3 1

Sample Output

2 1 3

分析：

因为这道题有两个变量需要我们考虑，所以先固定一个,使其先成为上升子序列后，然后只讨论一个，类似很久之前的一道拦截导弹的题，找最长上升子序列，然后每次找到后状态转移到下一个。

AC代码：

#include<stdio.h> #include<string.h> #include<algorithm> using namespace std; const int M=5e3+10; int t,n,ans; int book[M]; struct node{ int a,b; }s[M]; bool cmp(node x,node y){ if(x.b==y.b) return x.a<y.a; return x.b<y.b; } int main(){ scanf("%d",&t); while(t--){ ans=0; memset(book,0,sizeof(book)); scanf("%d",&n); for(int i=0;i<n;i++) scanf("%d%d",&s[i].a,&s[i].b); sort(s,s+n,cmp); for(int i=0;i<n;i++){ if(!book[i]){ book[i]=1; for(int j=i+1;j<n;j++){ if(s[i].a<=s[j].a&&!book[j]){ s[i].a=s[j].a; book[j]=1; } } ans++; } } printf("%d\n",ans); } return 0; }