代码思想: 给定一个序列输出出现次数最多的前10个
ls
="ufhaaiu867cqhlcl352sfsfah56463532daqAPJa"
count
={}
for i
in ls
:
count
[i
]=count
.get
(i
,0)+1
new
=sorted(count
.items
(),key
=lambda d
:d
[1],reverse
=True)
n
=0
print("元素 次数")
for i
in new
:
print("{:^4} {:^4}".format(i
[0],i
[1]))
n
+=1
if n
==10:
break
程序效果:
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