2020牛客NOIP赛前集训营-普及组（第二场） A-面试

题目链接

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题解

？模拟。

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代码

#include<cstdio> #include<iostream> using namespace std; int n,k[10]; char c; int main(){ scanf("%d", &n); for(int i = 1; i <= n; ++i){ k[1] = k[2] = k[3] = k[4] = 0; for(int j = 1; j <= 4; ++j){ c = getchar(); while(c > 'D' || c < 'A') c = getchar(); ++k[c - 'A' + 1]; } if(k[4] > 0 || k[3] > 1) printf("failed\n"); else if(k[4] == 0 && k[1] > 2) printf("sp offer\n"); else printf("offer\n"); } }