激活函数(神经网络激活函数的作用是什么?)
https://blog.csdn.net/program_developer/article/details/78704224
一维的卷积能处理多维数据
代码: nn.Conv2d(self, in_channels, out_channels, kernel_size, stride=1, padding=0, dilation=1, groups=1, bias=True))
参数: in_channel: 输入数据的通道数,例RGB图片通道数为3; out_channel: 输出数据的通道数,这个根据模型调整; kennel_size: 卷积核大小,可以是int,或tuple;kennel_size=2,意味着卷积大小2, kennel_size=(2,3),意味着卷积在第一维度大小为2,在第二维度大小为3; stride:步长,默认为1,与kennel_size类似,stride=2,意味在所有维度步长为2, stride=(2,3),意味着在第一维度步长为2,意味着在第二维度步长为3; padding: 零填充
举个例子🌰:
import torch import torch.nn as nn import torch.nn.functional as F x = torch.randn(10, 16, 30, 32, 34) # batch, channel , height , width print(x.shape) class Net_1D(nn.Module): def __init__(self): super(Net_1D, self).__init__() self.layers = nn.Sequential( nn.Conv1d(in_channels=16, out_channels=16, kernel_size=(3, 2, 2), stride=(2, 2, 1), padding=[2,2,2]), nn.ReLU() ) def forward(self, x): output = self.layers(x) log_probs = F.log_softmax(output, dim=1) return log_probs n = Net_1D() # in_channel,out_channel,kennel, print(n) y = n(x) print(y.shape)卷积计算(计算过程数学推导):
d = (d - kennel_size + 2 * padding) / stride + 1 x = ([10,16,30,32,34]),其中第一维度:30,第一维度,第二维度:32,第三维度:34,对于卷积核长分别是;对于步长分别是第一维度:2,第二维度:,2,第三维度:1;对于padding分别是:第一维度:2,第二维度:,2,第三维度:2; d1 = (30 - 3 + 22)/ 2 +1 = 31/2 +1 = 15+1 =16 d2 = (32 - 2 + 22)/ 2 +1 = 34/2 +1 = 17+1 =18 d3 = (34 - 2 + 2*2)/ 1 +1 = 36/1 +1 = 36+1 =37 batch = 10, out_channel = 16 故:y = [10, 16, 16, 18, 37]结果展示:
torch.Size([10, 16, 30, 32, 34]) Net_1D( (layers): Sequential( (0): Conv1d(16, 16, kernel_size=(3, 2, 2), stride=(2, 2, 1), padding=[2, 2, 2]) (1): ReLU() ) ) torch.Size([10, 16, 16, 18, 37])二维卷积可以处理二维数据
代码: nn.Conv2d(self, in_channels, out_channels, kernel_size, stride=1, padding=0, dilation=1, groups=1, bias=True))
参数: in_channel: 输入数据的通道数,例RGB图片通道数为3; out_channel: 输出数据的通道数,这个根据模型调整; kennel_size: 卷积核大小,可以是int,或tuple;kennel_size=2,意味着卷积大小(2,2), kennel_size=(2,3),意味着卷积大小(2,3)即非正方形卷积 stride:步长,默认为1,与kennel_size类似,stride=2,意味着步长上下左右扫描皆为2, stride=(2,3),左右扫描步长为2,上下为3; padding: 零填充 举个例子🌰:
输入数据X[10,16,30,32],其分别代表:10组数据,通道数为16,高度为30,宽为32
import torch import torch.nn as nn x = torch.randn(10, 16, 30, 32) # batch, channel , height , width print(x.shape) m = nn.Conv2d(16, 33, (3, 2), (2,1)) # in_channel, out_channel ,kennel_size,stride print(m) y = m(x) print(y.shape)卷积计算过程:
h/w = (h/w - kennel_size + 2padding) / stride + 1 x = ([10,16,30,32]),其中h=30,w=32,对于卷积核长分别是 h:3,w:2 ;对于步长分别是h:2,w:1;padding默认0; h = (30 - 3 + 20)/ 2 +1 = 27/2 +1 = 13+1 =14 w =(32 - 2 + 2*0)/ 1 +1 = 30/1 +1 = 30+1 =31 batch = 10, out_channel = 33 故: y= ([10, 33, 14, 31])结果展示:
torch.Size([10, 16, 30, 32]) Conv2d(16, 33, kernel_size=(3, 2), stride=(2, 1)) torch.Size([10, 33, 14, 31])