Codeforces——158A Next Round

小声BB

最近总是状态不好，不管是范围还是特例都有思考不周之处

题干

time limit per test：3 seconds memory limit per test：256 megabytes input：standard input output：standard output

“Contestant who earns a score equal to or greater than the k-th place finisher’s score will advance to the next round, as long as the contestant earns a positive score…” — an excerpt from contest rules.

A total of n participants took part in the contest (n ≥ k), and you already know their scores. Calculate how many participants will advance to the next round.

Input

The first line of the input contains two integers n and k (1 ≤ k ≤ n ≤ 50) separated by a single space.

The second line contains n space-separated integers a1, a2, …, an (0 ≤ ai ≤ 100), where ai is the score earned by the participant who got the i-th place. The given sequence is non-increasing (that is, for all i from 1 to n - 1 the following condition is fulfilled: ai ≥ ai + 1).

Output

Output the number of participants who advance to the next round.

Examples

Input 8 5 10 9 8 7 7 7 5 5

Output 6

Input 4 2 0 0 0 0

Output 0

Note

In the first example the participant on the 5th place earned 7 points. As the participant on the 6th place also earned 7 points, there are 6 advancers.

In the second example nobody got a positive score.

分析

就是跟第k名的人比分数，除了0分外，不比他小的就计次，这里要注意写循环，不要炫技，写for循环的结束条件时不考虑范围（说的就是我）

代码

#include<iostream> using namespace std; int main() { int a[100],n,k; cin >> n >> k; for(int i = 0;i < n;i++) cin >> a[i]; int std = a[k - 1]; int ct = 0; for(int i = 0;i < n;i++) if(a[i] >= a[k - 1] && a[i] != 0) ct++; cout << ct; return 0; }