pandas 遍历Dataframe

iterrows(): 按行遍历，将DataFrame的每一行迭代为(index, Series)对，可以通过row[name]对元素进行访问。itertuples(): 按行遍历，将DataFrame的每一行迭代为元祖，可以通过row[name]对元素进行访问，比iterrows()效率高。iteritems():按列遍历，将DataFrame的每一列迭代为(列名, Series)对，可以通过row[index]对元素进行访问。

示例数据

import pandas as pd inp = [{'c1':10, 'c2':100}, {'c1':11, 'c2':110}, {'c1':12, 'c2':123}] df = pd.DataFrame(inp) print(df) c1 c2 0 10 100 1 11 110 2 12 123

按行遍历iterrows():

import pandas as pd inp = [{'c1': 10, 'c2': 100}, {'c1': 11, 'c2': 110}, {'c1': 12, 'c2': 123}] df = pd.DataFrame(inp) for index, row in df.iterrows(): print(index,row['c1'], row['c2']) # 输出每一行 pass 0 10 100 1 11 110 2 12 123

按行遍历itertuples():

import pandas as pd inp = [{'c1': 10, 'c2': 100}, {'c1': 11, 'c2': 110}, {'c1': 12, 'c2': 123}] df = pd.DataFrame(inp) for row in df.itertuples(): print(getattr(row, 'c1'), getattr(row, 'c2')) # 输出每一行

按列遍历iteritems():

import pandas as pd inp = [{'c1': 10, 'c2': 100}, {'c1': 11, 'c2': 110}, {'c1': 12, 'c2': 123}] df = pd.DataFrame(inp) for index, row in df.iteritems(): print(index) # 输出列名 print(row[0], row[1], row[2]) # 输出各列