示例1:
#coding=utf-8 import re ret = re.match(".","M") print(ret.group()) ret = re.match("t.o","too") print(ret.group()) ret = re.match("t.o","two") print(ret.group()) # 运行结果: M too two示例2:[ ]
#coding=utf-8 import re # 大小写h都可以的情况 ret = re.match("[hH]","hello Python") print(ret.group()) # h ret = re.match("[hH]","Hello Python") print(ret.group()) # H ret = re.match("[hH]ello Python","Hello Python") print(ret.group()) # Hello Python # 匹配0到9第一种写法 ret = re.match("[0123456789]Hello Python","7Hello Python") # 7Hello Python print(ret.group()) # 匹配0到9第二种写法 ret = re.match("[0-9]Hello Python","7Hello Python") print(ret.group()) # 7Hello Python ret = re.match("[0-3,5-9]Hello Python","7Hello Python") print(ret.group()) # 7Hello Python # 下面这个正则不能够匹配到数字4,因此ret为None ret = re.match("[0-3,5-9]Hello Python","4Hello Python") print(ret.group()) # None 示例3:\d #coding=utf-8 import re # 普通的匹配方式 ret = re.match("嫦娥1号","嫦娥1号发射成功") print(ret.group()) # 使用\d进行匹配 ret = re.match("嫦娥\d号","嫦娥1号发射成功") print(ret.group()) # 运行结果: 嫦娥1号示例1:*
需求:匹配出,一个字符串第一个字母为大写字符,后面都是小写字母并且这些小写字母可有可无
#coding=utf-8 import re ret = re.match("[A-Z][a-z]*","M") print(ret.group()) ret = re.match("[A-Z][a-z]*","MnnM") print(ret.group()) ret = re.match("[A-Z][a-z]*","Aabcdef") print(ret.group()) 运行结果: M Mnn Aabcdef示例2:+
需求:匹配出,变量名是否有效 备注: (1)变量名只能是 字母、数字或下划线的任意组合 (2)变量名的第一个字符不能是数字 (3)关键字不能声明为变量名,例如as / lambda/ python/ else /class /global/ 等等
#coding=utf-8 import re names = ["name1", "_name", "2_name", "__name__"] for name in names: ret = re.match("[a-zA-Z_]+[\w]*",name) if ret: print("变量名 %s 符合要求" % ret.group()) else: print("变量名 %s 非法" % name) # 运行结果: # 变量名 name1 符合要求 # 变量名 _name 符合要求 # 变量名 2_name 非法 # 变量名 __name__ 符合要求示例3:?
需求:匹配出,0到99之间的数字
#coding=utf-8 import re ret = re.match("[1-9]?[0-9]","7") print(ret.group()) ret = re.match("[1-9]?\d","33") print(ret.group()) ret = re.match("[1-9]?\d","09") print(ret.group()) 运行结果: 7 33 0 # 这个结果并不是想要的,利用$才能解决示例4:{m}
需求:匹配出,8到20位的密码,可以是大小写英文字母、数字、下划线
#coding=utf-8 import re ret = re.match("[a-zA-Z0-9_]{6}","12a3g45678") print(ret.group()) ret = re.match("[a-zA-Z0-9_]{8,20}","1ad12f23s34455ff66") print(ret.group()) 运行结果: 12a3g4 1ad12f23s34455ff66练一练
题目1:匹配出163的邮箱地址,且@符号之前有4到20位,例如hello@163.com
E_mail = hello_world@163.com Ret = re.math(‘[a-zA-Z0-9_]{4,20}@163.com’,E_mail) 在正则中,点(.)表示任意一个字符,正则表达式如果写成"[/w]{4,20}@163.com$",那hello_world@1633com也会被匹配出来