Z变换:ztrans Z反变换:iztrans
>> f2
=((10*x
*x
))/((2*x
+1)*(5*x
+1))
f2
=
(10*x
^2)/((2*x
+ 1)*(5*x
+ 1))
>> iztrans(f2
)
ans
=
(5*(-1/2)^n
)/3 - (2*(-1/5)^n
)/3
>> ztrans(ans
)
ans
=
(5*z
)/(3*(z
+ 1/2)) - (2*z
)/(3*(z
+ 1/5))
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